The roots of the quadratic equation $2x^2 + x - 6 = 0$ are

The correct answer is $\dfrac{3}{2}, -2$

$2x^2 + x - 6 = 0$

⇒ $2x^2 + 4x - 3x - 6 = 0$

⇒ $2x(x + 2) - 3(x + 2) = 0$

⇒ $ (2x − 3)(x + 2)= 0$

⇒ $x = \dfrac{3}{2}, -2$